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Home/ Questions/Q 6979
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Asked: July 14, 20232023-07-14T11:23:53+05:30 2023-07-14T11:23:53+05:30In: Science (Physics, Chemistry, Biology etc)

A ball is kicked at 20m/s at an angle of 30° above the ground. What is the horizontal and vertical velocity?

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A ball is kicked at 20m/s at an angle of 30° above the ground. What is the horizontal and vertical velocity?
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  1. Emma
    2023-07-14T11:42:04+05:30Added an answer on July 14, 2023 at 11:42 am

    The horizontal velocity is 17.32 m/s and the vertical velocity is 10 m/s.

    To calculate the horizontal velocity, we can use the following formula:

    Code snippet

    v_x = u_x * cos(theta)

     

    Use code with caution. Learn more

    content_copy

    Where:

    • v_x is the horizontal velocity
    • u_x is the initial velocity
    • theta is the angle of projection

    In this case, we have:

    Code snippet

    v_x = 20 m/s * cos(30°)

    = 17.32 m/s

     

    Use code with caution. Learn more

    content_copy

    To calculate the vertical velocity, we can use the following formula:

    Code snippet

    v_y = u_y * sin(theta) + g * t

     

    Use code with caution. Learn more

    content_copy

    Where:

    • v_y is the vertical velocity
    • u_y is the initial velocity in the vertical direction
    • g is the acceleration due to gravity (9.8 m/s^2)
    • t is the time of flight

    In this case, we have:

    Code snippet

    v_y = 20 m/s * sin(30°) + 9.8 m/s^2 * t

    = 10 m/s

     

    Use code with caution. Learn more

    content_copy

    The time of flight can be calculated using the following formula:

    Code snippet

    t = 2 * v_y / g

     

    Use code with caution. Learn more

    content_copy

    In this case, we have:

    Code snippet

    t = 2 * 10 m/s / 9.8 m/s^2

    = 2.04 s

     

    Use code with caution. Learn more

    content_copy

    Therefore, the horizontal velocity of the ball is 17.32 m/s and the vertical velocity is 10 m/s.

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  2. Peter
    2023-07-14T11:42:03+05:30Added an answer on July 14, 2023 at 11:42 am

    The horizontal velocity is 17.32 m/s and the vertical velocity is 10 m/s.

    To calculate the horizontal velocity, we can use the following formula:

    Code snippet

    v_x = u_x * cos(theta)

     

    Use code with caution. Learn more

    content_copy

    Where:

    • v_x is the horizontal velocity
    • u_x is the initial velocity
    • theta is the angle of projection

    In this case, we have:

    Code snippet

    v_x = 20 m/s * cos(30°)

    = 17.32 m/s

     

    Use code with caution. Learn more

    content_copy

    To calculate the vertical velocity, we can use the following formula:

    Code snippet

    v_y = u_y * sin(theta) + g * t

     

    Use code with caution. Learn more

    content_copy

    Where:

    • v_y is the vertical velocity
    • u_y is the initial velocity in the vertical direction
    • g is the acceleration due to gravity (9.8 m/s^2)
    • t is the time of flight

    In this case, we have:

    Code snippet

    v_y = 20 m/s * sin(30°) + 9.8 m/s^2 * t

    = 10 m/s

     

    Use code with caution. Learn more

    content_copy

    The time of flight can be calculated using the following formula:

    Code snippet

    t = 2 * v_y / g

     

    Use code with caution. Learn more

    content_copy

    In this case, we have:

    Code snippet

    t = 2 * 10 m/s / 9.8 m/s^2

    = 2.04 s

     

    Use code with caution. Learn more

    content_copy

    Therefore, the horizontal velocity of the ball is 17.32 m/s and the vertical velocity is 10 m/s.

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    • Reply
    • Share
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